Here's one way to see if a number is even or odd.
if (n % 2 == 0)
// n is even
else
// in is odd
Type: Posts; User: literallyjer
Here's one way to see if a number is even or odd.
if (n % 2 == 0)
// n is even
else
// in is odd
AMIS Technology blog » Blog Archive » Oracle RDBMS 11gR2 - Solving a Sudoku using Recursive Subquery Factoring
What is line 28?
You program is returning 1 because that is what you told it to do. It is apparent (based on what you've said) that your code is getting to the first return statement before the last one. Since that...
For some reason it didn't click that you were using Swing. You have to be really careful when using multiple threads with Swing. I suggest you look into SwingUtilities.invokeLater() and...
With out actually running your code, I would assume it has to do with the "return found" inside the last for loop. (Which also seems to be missing the "for" part of it..)
A Timer itself does not know how to read from a text file.
You would have to read from the text file first (See the thread "Scanner or BufferedReader" for help on that), then parse your data, and...
It really doesn't matter where the input comes from. For example:
Scanner in = new Scanner(new File("myfile.txt");
BufferedReader in = new BufferedReader(new FileReader(new File("myfile.txt"));...
Ooooh, but I wanted to be clever! *pouts*
Haha, it is still a fun little exercise.
To check if a number is even, you can do this:
if (num % 2 == 0)
Thread.sleep() -- See the Java API for more details.
The Java API: Java Platform SE 6
This is a perfect opportunity for you to read the Java API for Maps and Strings ;-)
The Java API: Java Platform SE 6
Where do you get this null pointer?
I have started writing a Sudoku solver myself. So far I have written all the setup code. Now we are both stuck at the same point: how to go about solving the...
Do you have any ideas?
Half of the fun of coding is the thought that goes into it ;-)
Do you mean adding possible values to solve the puzzle? Well, I am not an expert sudoku puzzle solver, so I am not exactly sure how to proceed at the moment. How would you solve the puzzle in your...
You are very welcome :-)
I would still do it the way I started doing it above.
I would make the file look like this:
1,2:4
4,9:8
x,y:z
where 1 is the horizontal position (the x value, or the first value in the...
I am assuming that line 14 is this:
OurLinkedList <String>cloned = (OurLinkedList<String>)myList.clone();
If that's the case, then you are trying to cast a LinkedList into your OurLinkedList....
From the looks of it, you already are using a two dimensional array...
Since that's the case, why are you creating an array of Cells of size 81?
Why does your clone method repeatedly (assuming size is greater than 1) add "A" into the cloned list and not the values of the list it is cloning?
It might be easier to use a two dimensional array here, as it more accurately represents a Sudoku square.
public class Sudoku {
private Cell[][] square = new Cell[9][9];
public...
You need to loop through the array and check each value. If the value is of x, then change that value to y.
Here is some pseudo code:
a = new array()
for (each element in a) {
if...
It really is up to the professor. When I took CS 1 at college, my professor taught us Scanner. Yet, two semesters later a new professor taught the course with BufferedReader. (However, I believe he...
Other than what helloworld said, Scanner internally buffers its input using a CharBuffer. Whereas a BufferedReader is meant for generic use for buffering characters from some sort of input.
There is nothing non-sequential about recursion.
Recursion means that a method calls itself within its own method body. As long as there is a case where the recursion can be stopped, then you will...