If you can guarantee that your number can fit inside an int (or a long), do this:
long temp = 100.0 * f;
f = temp/100.0;
Or, in one line:
f = ((long)(100.0*f))/100.0;
Type: Posts; User: helloworld922
If you can guarantee that your number can fit inside an int (or a long), do this:
long temp = 100.0 * f;
f = temp/100.0;
Or, in one line:
f = ((long)(100.0*f))/100.0;