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You have a pre-mature return statement. remove the return (((double)count)/str2.length());

Also, I think you wanted to check if it matched by atleast that percentage, right?

If so, you need to...

err... oops. The return ((double)count)/str2.length(); should be the percentage of common letters between str1 and str2. Just compare that with N and return true or false appropriately.

Oh wow, haha that's the wrong topic to be posting that in. For some reason I thought this was your other topic about substrings :)

So the letters in str2 can appear anywhere in str1?


for (int...

for(int i = 0; i < str1.length(); i++)
{
for (int j= 0; j < str2.length();j++)
{
if (i+j >= str1.length())
{
// test wrap-around bit
...

I think it's a typo, but you need to declare int data types lower case, and there is a missing space. Also, general convention in java is to name variables/methods starting with lower case letters,...