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Thanks very much for your help :)

{1, 2, 3, 4, 5}

n = 3

nth element = 3rd element in stack, which is 3.

So you would pop() three times leaving {4,5}.

If it was j it would be exactly the same then? i.e

Thanks very much for the replies :)

I have added print statements and I can see exactly what is going on!

If I was going to take this one step further, (given integer 'n') and set j to the nth...

It created two stacks s & s2.

I then added s.push("n"); and s.push("m"); giving n & m in the stack1.... is this about right so far?

thanks

Yes this is a different question. How would I go about making a program that does what I want?

Creating my stacks (s) and (s2) - Stack s = new Stack();
...

Hi everone, I have been doing java for around a year now :)
I'm not looking for somebody to give me an answer but for guidance and help.

This is the question:

I have a stack called 's'....