You can use
which is actually root 10 * log(x) to find it also. or read up on babylonian Method, the true iterative method, for those numbers whose square root is not an integer such as 8.
Chris
Type: Posts; User: Freaky Chris
You can use
which is actually root 10 * log(x) to find it also. or read up on babylonian Method, the true iterative method, for those numbers whose square root is not an integer such as 8.
Chris
Math.sqrt(n);
Easy :) I'm sure you can work it out
Regards,
Chris