You have two variables and only one equation. The way to solve this problem is to 'fix' one of the variables and find a value that works for the other. I guess you can derive a minimum and a maximum...
Type: Posts; User: Sean4u
You have two variables and only one equation. The way to solve this problem is to 'fix' one of the variables and find a value that works for the other. I guess you can derive a minimum and a maximum...
Well you don't have a quadratic equation there, what you have is 4t + 3s = 300 - it's the same kind of equation (y = mx + c) that's used to specify a straight line on a graph. You can't draw a line...