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Thread: calling ajax returning undefined value to called script (ddt is the variable)

  1. #1
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    Post calling ajax returning undefined value to called script (ddt is the variable)

     
     
    // calling script
     
    var ddt;
    			for(i=0;i<full_id_array.length;i++)
    			{
    				if(full_ck_array[i]=='yes')
    				{	
    					idname=full_id_array[i];					
    					ddt += primary_general(idname);  // called java script
    					alert(ddt);
    				}
    			}
    			alert('final...'+ddt);

     
    function primary_general(k)
    		{	
    			var idname=k, xyz = "#"+idname, xverified='0';	
    			var y = $(xyz).val();
     
    			$.ajax(
    			{					
    				type: "POST",
    				url: checkingfilename,
    				data: {async: false,						
    						pass_type_array: tparray,
    						pass_error_array: erarray,						
    						pass_element_array: idarray,
    						pass_element_maxlength: 0, 						
    						pass_element_id: k, 
    						pass_element_value: y,
    						pass_operation: 'ind',},
    				success: function(data)
    				{					
    					var cidnm = $.parseJSON(data);					
    					$(cidnm.error_id).html(cidnm.error_mess);
    					if(cidnm.error_mess != '')
    					{
    						xverified = '1';
    					}
    					return xverified;
    				},
    				error: function(data)
    				{
    					xverified = '1';
    					return xverified;
    				}
    			});
    		}

  2. #2
    Super Moderator Norm's Avatar
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    Default Re: calling ajax returning undefined value to called script (ddt is the variable)

    Moved from java section. javascript != java
    If you don't understand my answer, don't ignore it, ask a question.

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