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Thread: How to call Servlet using ajax

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    Default How to call Servlet using ajax

    Excuse me,
    My name is Pragathi.
    What am i asking is how to call servlet using ajax sample examples.
    So please give me suggestions to me and mail me some examples on it.

    I have a form that is designed in a JSP. This form has 2 dropdown lists such that first one has fixed options and second one has to be populated dynamically (according to the option selected by user in first dropdown list) from the without database . This is the task that I have to perform.


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    Default Re: How to call Servlet using ajax

    Hi,

    I understand what you want to do in your application. I guess you have not searched in web.

    Please refer to Call servlet from Ajax - Stack Overflow
    Thanks and regards,
    Sambit Swain

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    Default how to get output for this ajax using code. Code is shown bellow.

    Hi,
    i'm beginner for this ajax program. So please give me suggestions and help me also.
    Here my doubt is, here is two drop down lists so when 1st one(dropdown) is in static position and 2nd(dropdown) is in dynamical position by usage of 1st one. And also reversal.
    In this following code i use this (findState.php?). But with out that .php file & with out data base(DB) how can i get out put by using ajax.


    <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
    <html>
    <head>
    <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
    <title>Insert title here</title>
    </head>
    <body>
    <input type="text" name="othstate" value="" class="textBox">
    <form method="post" name="form1">
    <select style="background-color: #ffffa0" name="country" onchange="getState(this.value)">
    <option>Select Country</option>
    <option value="223">USA</option>
    <option value="224">Canada</option>
    <option value="225">England</option>
    <option value="226">Ireland</option>
    </select>

    <select style="background-color: #ffffa0" name="state">
    <option>Select Country First</option>
    </select>
    <script>
    function getState(countryId)
    {
    var strURL="findState.php?country="+countryId;
    var req = getXMLHTTP();
    if (req)
    {
    req.onreadystatechange = function()
    {
    if (req.readyState == 4)
    {
    // only if "OK"
    if (req.status == 200)
    {
    document.getElementById('statediv').innerHTML=req. responseText;
    } else {
    alert("There was a problem while using XMLHTTP:\n" + req.statusText);
    }
    }
    }
    req.open("GET", strURL, true);
    req.send(null);
    }
    }
    </script>
    </body>
    </html>

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    Default Re: How to call Servlet using ajax

    Welcome to the Forum! Please read this topic to learn how to post your code correctly along with other useful info for newcomers.

    Please don't start multiple threads for the same topic. If the question has evolved, just say so, and keep going. You can also ask ask a mod to retitle or move the thread, if appropriate.

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    Default Re: How to call Servlet using ajax

    hi,

    document.getElementById('statediv').innerHTML=req. responseText;

    In this statement, you are not created the div element. So create div element within body tage like below

    <div id="statediv"></div>

    Try this it may helpful

    Thanks,

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    Default Re: How to call Servlet using ajax

    Create a div id for the 2nd drop down. responsetext should be set in the inner HTML of 2nd drop down element.

    Follow the link ajax - populate dropdown on change of another using servlet - Stack Overflow

    Sorry, currently I dont have the exact workspace and jar files ready to code and test the solution before giving it to you. Please refer to the link above and give a try, hopefully by day after tomorrow I will set up a new project with your content and provide a better solution.
    Thanks and regards,
    Sambit Swain

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