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Thread: Keeping track of found objects in array and smallest value

  1. #26
    Super Moderator Norm's Avatar
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    Default Re: Keeping track of found objects in array and smallest value

    I suggested that you create a NEW array of the desired size.
    Then copy the elements from the old array to the new array. The Arrays class has a method to do that.

    ArrayList is a java class. See the API doc for how to create one and what methods it has.
    If you don't understand my answer, don't ignore it, ask a question.

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    Default Re: Keeping track of found objects in array and smallest value

    I have set my original 2 arrays to 10, so now if I make a third array to copy my 2nd array to, then there will be some slots that will be filled with 0's and those will get copied over. I guess I should of done your array list way in the beginning but I dont think I am allowed use arraylist for this.

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    Default Re: Keeping track of found objects in array and smallest value

    If you have an array with 10 slots with the first 6 elements containing data
    and create a new array with 6 slots
    and copy the first 6 slots from the first array to the second array, (See the Arrays class for a method)

    there will NOT be any empty slots with 0s in the new array.
    If you don't understand my answer, don't ignore it, ask a question.

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    Default Re: Keeping track of found objects in array and smallest value

    Im aware of that but am I just trying to make it fool proof, as in what if there happens to be 7 or n + 1 matches then it has to be an array of 7 elements, and since my array is one of the first things I would declare I would not be able to change it.

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    Default Re: Keeping track of found objects in array and smallest value

    Create the new array WHEN you know how large it needs to be. The new code I've described would replace this statement:
    valueFound.length = count;

    After the copy was made, valueFound could be assigned the new array.
    If you don't understand my answer, don't ignore it, ask a question.

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