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Thread: Working with log math function

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    Default Working with log math function

    I want to output to calculate the following:

    0 - (3/6)logbase2(3/6) = 1/2

    I have this in my program:
    double ratio = 3/6;
    x  = x - (ratio * (logbase2(ratio)));

    which should equal .5 but I keep getting 0.326634259978281

    what am I doing wrong?

    Edit: I figure it out. I should be using:
    (ratio * Math.log(ratio)/Math.log(2))
    Last edited by colerelm; October 15th, 2012 at 06:36 PM.


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