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Thread: unreachable statement?

  1. #1
    Java kindergarten chronoz13's Avatar
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    Default unreachable statement?

    public class Sample {
     
        private static final int MIN_NUMBER = 5;
     
        private int number;
     
        public int set(double num) {
     
            number = (int) num;
     
            if (minimumNumber()) {
     
                System.out.println("SMALLER");
     
                return number - number;
            }
            else {
                System.out.println("LARGET THAN THE MINIMUM NUMBER!");
     
                return number + 10000;
            }
     
            if ( number == 10000) {
     
                System.out.println("SO LARGE");
            }
     
            return number + 100;
        }
     
        public boolean minimumNumber() {
     
                return number <= MIN_NUMBER;
        }
     
    }

    having some errors here
    why?


  2. #2
    Super Moderator Json's Avatar
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    Default Re: unreachable statement?

    In your set method this code will never be reached.

            if ( number == 10000) {
     
                System.out.println("SO LARGE");
            }
     
            return number + 100;

    This is because the if statement above it will either return something if it is true and if it isn't it will also return something. Therefore your method will have returned something before reaching the mentioned code.

    // Json

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