Thread: Coin Loop Selective Print Statement Problem

This is a homework assignment and I am stuck and I have researched every book I know that talks about loops.
I am required to print the loop at every 25th loop up to 500, i.e. 1-25th, 26-75th, 100th, 125th, etc.

I guess another way of stating my problem is that I want to sum up the toss results for every 25 loop iterations up to 500. Can someone please explain how I can do this? Right now my code is printing all 500 loops.

 package coin;
 
import java.util.Random;
 
public class Coin 
{
    public static void main(String[] args) 
    {
       int heads =0, tails =0, tossResult, total;
       double tailsPercent, headsPercent;
       Random coinTossing = new Random();
 
       System.out.println("Number of tosses\t\tNo. of Heads\\ % \t\tNo. of Tails\\ %");
 
       for (int i = 1; i <= 50; i++)
       {
           tossResult = coinTossing.nextInt(2);
 
           if (tossResult == 0)
 
           {
              heads++;
           }
 
           else
 
           {
              tails++;
           }
 
           total = heads + tails;
           headsPercent = ((double)(heads)/total)*100;
           tailsPercent = ((double)(tails)/total)*100;
 
           System.out.printf("\t%d\t\t\t\t%d  %.1f\t\t%d  %.1f", total, heads,
                   headsPercent, tails, tailsPercent);
           System.out.println();
           }
 
       }
    }

If you know a good link that explains this too, please send it my way. Thank you!

Your loop counter is i. You want to do something special for i = 25, i = 50, i = 75, ..., Every value of i that is divisible by 25, ...

In Java, you can find out whether an integer is divisible by another integer by using the "remainder" operator (the '%' sign), which divides the first operand by the second and returns the remainder as its result.


That is to say, for integers a and b:

a is divisible by b if (and only if) a%b is equal to zero.

Cheers!

Z