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Thread: Array and Loop?

  1. #1
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    Default Array and Loop?

    Goal: To count the number of times each letter (a-z, both upper and lower case) appears in a file. Lower and upper case versions count as the same letter. So a's and A's both will be counted as a's. I am supposed to use an array

    So I have three problems.
    1. I'm not sure if I should do letters (a-z) for my array or numbers (0 - 25).
    2. Would a while loop be the best? Or a for loop?
    3. How do I combine the use of the scanner and the array in the loop?

    My code so far:

    /*
     * Count the number of times a letter appears in a text file
     * 
     * @author Kristen Watson
     * @version 11/12/2012
     * 
     */
     
    import java.util.Scanner;
    import java.io.File;
     
    public class LetterInventory{
        public final static String filename = "testFile.txt";
     
        public static void main(String[] args) {
            Scanner inputFile = null;
            try {
                inputFile = new Scanner(new File(filename));
            } catch (Exception e) {
                System.out.println("File could not be opened: " + filename);
                System.exit(0);
            }
     
            countOccurrences(inputFile);
            displayTable();
        }
     
     
        /*
         * constructor
         * inventory of letters with maximum of 26 different letters
         */
        public LetterInventory(){
            char []inventory = {'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i',
                  'j', 'k','l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 
                  'v', 'w', 'x', 'y', 'z'};  
     
        }
     
        /*
         * scanner takes information from the file and counts the letters 
         */
     
        public static void countOccurrences(Scanner file) {
     
             // file.next();
     
     
        }
     
     
     
        /*
         * output of the counted letters
         */
        public static void displayTable(){
            System.out.println("a:" );
            System.out.println("b:" );
            System.out.println("c:" );
            System.out.println("d:" );
            System.out.println("e:" );
            System.out.println("f:" );
            System.out.println("g:" );
            System.out.println("h:" );
            System.out.println("i:" );
            System.out.println("j:" );
            System.out.println("k:" );
            System.out.println("l:" );
            System.out.println("m:" );
            System.out.println("n:" );
            System.out.println("o:" );
            System.out.println("p:" );
            System.out.println("q:" );
            System.out.println("r:" );
            System.out.println("s:" );
            System.out.println("t:" );
            System.out.println("u:" );
            System.out.println("v:" );
            System.out.println("w:" );
            System.out.println("x:" );
            System.out.println("y:" );
            System.out.println("z:" );   
     
        }
     
     
     
        public static void resetInventory(){
     
     
        } 
    }



    Driver provided for the code

    *  It opens a test file and then uses a student written
     *  class called LetterInventory to count the number of
     *  times each letter occurs in the test file.
     * 
     * @author Clark Olson
     * @version 11/7/2012
     */
     
    import java.util.Scanner;
    import java.io.File;
     
    public class LetterCounter {
     
        public final static String filename = "testFile.txt";
     
        // Driver to test LetterInventory class
        public static void main(String[] args) {
            Scanner inputFile = null;
            try {
                inputFile = new Scanner(new File(filename));
            } catch (Exception e) {
                System.out.println("File could not be opened: " + filename);
                System.exit(0);
            }
     
            LetterInventory inventory = new LetterInventory();
            inventory.countOccurrences(inputFile);
            inventory.displayTable();
            inventory.resetInventory();
        }
     
    }


  2. #2
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    Default Re: Array and Loop?

    Here's the way that I see it:

    You need an array of 26 integers. Each element of the array will hold the count of a particular character 'a' through 'z'. You could call the array counters. The counters array is declared and initialized in the LetterInventory class.

    counters[0] will hold the count for the character 'a'
    counters[1] will hold the count for the character 'b'
    .
    .
    .
    counters[25] will hold the count for the character 'z'



    Then in the countOccurrences method of that class:

    Make a loop that reads lines from the given Scanner file.  Each line is read into a String.
    A conventient form of loop can be something like:
     
            while (file.hasNextLine()) {
                String line = file.nextLine();
                // Do something with the String
            }
     
    What is that "something that you do with the String?
     
    Well...
    Convert each String read by the Scanner nextLine() method to lower case and then do something like the following
     
    Make a loop that goes through all of the characters in the String.
     
    Inside the loop it goes something like this:
        Use the charAt() method to retrieve the current character
     
        Declare an integer variable named x and set x equal to the integer value of the current character minus 'a'.
        (That means that 'a' becomes 0, 'b' becomes 1, ... , 'z' becomes 25)
     
        If x is greater than or equal to zero and x is less than the number of elements in the counters array, then
          Increment counters[x]
        End if
       (That means that spaces and punctuation and everything other than a alphabetic characters will be ignored.)

    Finally...

    The displayTable method would print out the value of each of the counters in some kind of loop like
            for (int i = 0; i < counters.length; i++) {
                System.out.printf("%c: %5d\n", (char)(i + 'a'), counters[i]);
            }

    So a file containing the single line "The quick brown fox jumps over the lazy dog." would have the following output:
    a:     1
    b:     1
    c:     1
    d:     1
    e:     3
    f:     1
    g:     1
    h:     2
    i:     1
    j:     1
    k:     1
    l:     1
    m:     1
    n:     1
    o:     4
    p:     1
    q:     1
    r:     2
    s:     1
    t:     2
    u:     2
    v:     1
    w:     1
    x:     1
    y:     1
    z:     1



    Cheers!

    Z

  3. The Following User Says Thank You to Zaphod_b For This Useful Post:

    Kristenw17 (November 16th, 2012)

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