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Quicker equality check?
I have an if statement and the entry condition requires the checking equality of a character against several other characters. Is it possible to put these several characters into a list to shorten the code? At the moment I have
if (str.charAt(i) != '*' && str.charAt(i) != '/' && str.charAt(i) != '{' && str.charAt(i) != '}'... && str.charAt(i) != '\t' && str.charAt(i) != ' ' ){ lineHolder += str.charAt(i); }
Clearly this is an inefficient way of doing things..
Any ideas?
Cheers
Last edited by Shaybay92; March 9th, 2012 at 10:32 PM. Reason: Realised the expression was wrong.. but fixed it now.
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Re: Quicker equality check?
A couple of caveats: shorter code != quicker execution as your question presupposes. Secondly there is quicker and quicker: the hearts of people at the base of a mountain beat more quickly than those at the top (and their lives are correspondingly shortened). It's a general relativistic effect and it is simply *not* worth worrying about (unless your clocks are launched into space as part of a military grade GPS system in which case the clock speed in a gravitational field matters). The time savings you are chasing are, similarly, more theoretical than real.
There is a String method that will test whether a character is present in a String and that could be used here. The resulting code would be more readable and that matters more than speed.
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