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Thread: unreachable statement Again?

  1. #1
    Java kindergarten chronoz13's Avatar
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    Default unreachable statement Again?

        public static void main(String[] args) {
     
            long targetNumber,
                 guessNumber;
     
            targetNumber = 34;
            System.out.println("Target Number Is:  " + targetNumber);
     
            do {
     
               guessNumber = (int) (Math.ceil(Math.random() * 100));
               System.out.println("Guess Number Is:  " + guessNumber);
            }
            while (true);
     
            if (guessNumber == targetNumber) {   // my compiler is displaying this part as "Unreachable statement"
     
                System.out.println("\n");
                System.out.println("Match Number Is:  " + guessNumber);
                System.exit(0);
            }
        }
    }

     if (guessNumber == targetNumber) {   // my compiler is displaying this part as "Unreachable statement"
    why?


  2. #2
    Super Moderator Json's Avatar
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    Default Re: unreachable statement Again?

    When do you think your code will get past this do while loop?

           do {
     
               guessNumber = (int) (Math.ceil(Math.random() * 100));
               System.out.println("Guess Number Is:  " + guessNumber);
            }
            while (true);

    // Json

  3. #3
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    Default Re: unreachable statement Again?

    Quote Originally Posted by chronoz13 View Post
        public static void main(String[] args) {
     
            long targetNumber,
                 guessNumber;
     
            targetNumber = 34;
            System.out.println("Target Number Is:  " + targetNumber);
     
            do {
     
               guessNumber = (int) (Math.ceil(Math.random() * 100));
               System.out.println("Guess Number Is:  " + guessNumber);
            }
            while (true);
     
            if (guessNumber == targetNumber) {   // my compiler is displaying this part as "Unreachable statement"
     
                System.out.println("\n");
                System.out.println("Match Number Is:  " + guessNumber);
                System.exit(0);
            }
        }
    }

     if (guessNumber == targetNumber) {   // my compiler is displaying this part as "Unreachable statement"
    why?

    it is a infinite loop. control never come out of do while loop upto stack overflow

  4. #4
    Java kindergarten chronoz13's Avatar
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    Default Re: unreachable statement Again?

    ahh ok ok.. its an infinite loop.The program will only read and stay at the loop's body..
    and it wont have any chance to execute or to reach the following statements after it because it will loop forever...

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