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Thread: Lost on Java Threads

  1. #1
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    Default Lost on Java Threads

    Hello,

    Please, this question is from the OCP Java SE 6 Programmer Practice Exams textbook, Assessment Test 2 question 8. Below is the code for the question.

    public class Salmon extends Thread {
     
    	public static long id;
     
    	public void run(){
    		for(int i=0; i<4;i++){
    			if(i==2 && id==Thread.currentThread().getId()){
    				new Thread(new Salmon()).start();
    				throw new Error();
    			}
    			System.out.print(i + " ");
    			System.out.println("programme got past Error!!");
    		}
    	}
    	public static void main(String[] args) {
     
    		Thread t1 = new Salmon();
    		id = t1.getId();
    		t1.start();
    	}
     
    }

    When I ran the code, below is my output:

    0
    programme got past Error!!
    1
    programme got past Error!!
    Exception in thread "Thread-0" java.lang.Error
    at org.OCP.JSE6.Exercises.Assessment1.Salmon.run(Salm on.java:15)
    0
    programme got past Error!!
    1
    programme got past Error!!
    2
    programme got past Error!!
    3
    programme got past Error!!
    My questions are as follow:
    1.why was there an exception in thread after i was 1 and then the programme continued again. I just want to understand the output.

    2. I thought since there was an exception, the programme should crash but that wasn't the case, the programme continued after the new Error() statement. Why is this?

    Thanks


  2. #2
    Crazy Cat Lady KevinWorkman's Avatar
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    Default Re: Lost on Java Threads

    1: Because you're creating another Thread. Only the first Thread will hit the Exception.

    2: The Thread that encountered the Exception will exit. The rest will not.
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