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Thread: Java string cut help...

  1. #1
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    Default Java string cut help...

    Hi all, was hoping to get some help with this.

    If I am given a string such as:
    REG20140509-0001

    I want to cut out the year/month/day, so in this case '20140509'.
    I know that the characters in front of the date will always be letters, not numbers, but I don't know how many. Three in the above example, but could be more or less.
    I do know that the date will always be followed by a dash and four digits.

    Thanks for any help!!!!!!


  2. #2
    Super Moderator Norm's Avatar
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    Default Re: Java string cut help...

    One idea:
    find the "-" and backup x characters over the date and use the substring method.
    If you don't understand my answer, don't ignore it, ask a question.

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    Default Re: Java string cut help...

    Quote Originally Posted by Norm View Post
    One idea:
    find the "-" and backup x characters over the date and use the substring method.
    Thanks Norm. I've used the substring method before, but not sure how to get it to work right to left?

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    Default Re: Java string cut help...

    how to get it to work right to left?
    It doesn't directly.
    The starting index is computed from the location of the "-" by subtraction.
    If you don't understand my answer, don't ignore it, ask a question.

  5. #5
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    Default Re: Java string cut help...

    Hi!
    You can first split the string by '-' character, so you will have "REG20140509" and store into a String variable (let's say date).
    After that you can apply a regexp over this string. Use "\\w" as a pattern.
    Then you will extract a substring from date variable. (ex: date.substring(matcher.end()+1); ) and you will get "20140509".

    Hope this helps.

    --- Update ---

    Sorry, I made a mistake.
    Use "\\d" pattern. And after that date.substring(matcher.start()) will return "20140509"

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