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Thread: Application that determines and prints odd, even and zero digit in an integer value

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    Default Application that determines and prints odd, even and zero digit in an integer value

    howdy,

    Another problem I've hit a wall with.

    The problem is to implement an application that determines and prints the number of odd, even, and zero digits in an integer value read from the keyboard.

    I can't think how to split the int up to check the individual values.

    Any tips?

    (I'm still new to this and haven't gone onto arrays yet, so if possible could a solution be found that is still quite basic)

    Many thanks,


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    Default Re: checking individual digits of an int

    Hello Konnor,

    You can split the given int into individual values by using the java Split function.

    I will write you a quick example ASAP but for now I suggest you check Google so you can get familiar with it.
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    mmm.. coffee JavaPF's Avatar
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    Wink Re: checking individual digits of an int

    Because the Split function needs a delimiter, and your int value wont contain one suitable I have had to use another method to split the intager after each number.

    Take a look at this code. The given int value is split after each number and put into an Array which you can then work with..

    import java.util.Scanner;
     
    public class Konnor2 {
     
        public static String stringInt;
     
        public static void main(String[] args) {
     
              System.out.println("Enter Integer Value: ");
              Scanner sc = new Scanner(System.in);
              stringInt = sc.next();
     
              String splitInt[] = new String[stringInt.length() / 1];
     
              for(int a = 0; a < splitInt.length; a++){
                  splitInt[a] = stringInt.substring(a * 1, a * 1 + 1);
                  System.out.println(splitInt[a]);
              }
        }
     
    }
    Let me know if you need help with coding the rest...
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