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Thread: problem in j2me

  1. #1
    Junior Member
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    Default problem in j2me

        public Student[] getStudents()
        {
            Student[] student=null;
            try
            {
                int pin=0;String name=null;
                byte[] byteInputData = new byte[100];
                RecordStore rs=Utility.getStudentRecordStore();
                ByteArrayInputStream inputStream = new ByteArrayInputStream(byteInputData);
                DataInputStream inputDataStream =new DataInputStream(inputStream);
                int noOfRecords=rs.getNumRecords();
                student=new Student[noOfRecords];
                for (int x = 1; x <= rs.getNumRecords(); x++)
                {
                    rs.getRecord(x, byteInputData, 0);
                    name=inputDataStream.readUTF();
                    pin=inputDataStream.readInt();
                    student[x-1].setName(name);
                    student[x-1].setPin(pin);
                    inputStream.reset();
                }
                inputStream.close();
                inputDataStream.close();
                return student;
            }
            catch (Exception error)
            {
            }
            return student;
        }


    QQ. Above method is not returning array of students although the student.length is providing a proper answer please help me
    Last edited by Sunil Raghuvanshi; March 9th, 2010 at 05:59 AM.


  2. #2
    Member Darryl.Burke's Avatar
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    Default Re: problem in j2me

    Don't eat exceptions. At the very least, print the stack trace.
      catch (Exception error) {
        error.printStackTrace();
      }
    Also, it's never recommended to catch Exception but rather the specific Exception subclass.

    db

  3. The Following User Says Thank You to Darryl.Burke For This Useful Post:

    JavaPF (March 18th, 2010)

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