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Thread: null pointer exception in "rs.next()"

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    Unhappy null pointer exception in "rs.next()"



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    Default Re: null pointer exception in "rs.next()"

    Your ArrayList's size is 1, then you call next() function twice. Exception will occur.
    When you call the second time iter.next(), there is null pointer exception due to "null.next"

    List tmpList = new ArrayList();
    tmpList.add(new Long(1));
    for (Iterator iter = tmpList.iterator(); iter.hasNext(); ) {
    	iter.hasNext();
    	iter.hasNext();
    }

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    Default Re: null pointer exception in "rs.next()"

    Quote Originally Posted by conniesookie View Post
    Your ArrayList's size is 1, then you call next() function twice. Exception will occur.
    When you call the second time iter.next(), there is null pointer exception due to "null.next"
    Calling next() on an iterator when no more elements left should result in a NoSuchElementException not a NullPointerException.

    Given very little information has been given, we are left to guessing and I can only guess rs refers to a ResultSet. What is null on the line that throws the Exception?

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