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Thread: Array Index Out of bounds?

  1. #1
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    Default Array Index Out of bounds?

    ]public static int[] encode(int array[]) throws FileNotCompressedException 
    	{
    	    int[] count=new int[array.length];
    		int[] Tarray=new int[array.length];
    		int j=0;
    		int c=0;
    		int NewArray[]=new int[array.length];
    		System.out.println(array[2]);
    		for (int i=0; i<array.length; i++)
    		{	
    			if(array[i]==array[i+1])
    			{
    				if(count[j]==0)
    				{
    					count[j]++;
    				}
    				count[j]++;
    			}
    			else
    			{
    				Tarray[c]=array[i];
    				c++;
    				j++;
     
    				if(count[j]==0)
    				{
    					count[j]++;
    				}
     
    			}
     
    		}
    		if(count.length+Tarray.length>=array.length)
    		{
     
    			throw new FileNotCompressedException();
    		}
    		else
    		{	int a=0;
    			int k=0;
    			while(a<NewArray.length)
    			{	
     
    				NewArray[a]=count[k];
    				NewArray[a+1]=Tarray[k];
    				a=a+2;
    				k++;
    			}
    			return NewArray;
    		}
     
     
    	}

    This is a small part of my code but to keep it short, i read from a file that has 1000's of int then i need to sort them in a special way but when i use my for loop to begin my sort i get that error on array[i]=array[i+1]; that says array index out of bounds but when i print array[1000] or any other it works fine;


  2. #2
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    Default Re: Array Index Out of bounds?

    Let's say that your array has 1000 cells which would mean it has indices 0-999. Your for loop would use i from 0-999, the problem is when you add 1 you would get 1000 which is not an index in the array hence the index out of bounds.

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