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Thread: How to validate a given URL

  1. #1
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    Default How to validate a given URL

    Hi all,
    I want to validate componentTextField, if these field is null or left blank and click the enter button, it must display an error message. Also need to validate the URL that is entered.
    Can anyone help in this regard.
    Thanks in advance.
    Last edited by HelloAll; March 1st, 2011 at 12:23 AM.


  2. #2
    mmm.. coffee JavaPF's Avatar
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    Default Re: How to validate a given URL

    Hello,

    Take a look at this code example - http://www.javaprogrammingforums.com...pressions.html

    You can put the code here:

        enterbutton.setText("Enter");
        gridConstraints.gridx = 1;
        gridConstraints.gridy = 5;
        getContentPane().add(enterbutton, gridConstraints);
        enterbutton.addActionListener(new ActionListener()
        {
        	public void actionPerformed(ActionEvent e)
        	{
        		enterbuttonActionPerformed(e);
        		// validate
        	}
        });

    You can check if something has been entered in the URLTextField by:

        		if(URLTextField.getText().equals("")){
        			//nothing has been entered
        		}
        		else{
        			//validate
        		}
    Please use [highlight=Java] code [/highlight] tags when posting your code.
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  3. The Following User Says Thank You to JavaPF For This Useful Post:

    HelloAll (February 28th, 2011)

  4. #3
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    Thumbs up Re: How to validate a given URL

    Thanks for your help. Using Regular expression was able to validate given URL.

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