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Thread: Why is this working?

  1. #1
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    Default Why is this working?

    Hi there.
    I was trying some code on java exception handling. I expected it to throw an error, but it returned the arguement.
    What is going on?

     
    public class Main{
     
    public static void main(String[] args) throws Exception {
     
            squarePrinter("I am square");
     
        }
     
     
    public static <Square> void squarePrinter(Square squareObject){
     
            try
            {
     
                System.out.print(squareObject);
     
            }
            catch (IllegalStateException e)
            {
                System.out.println("You cannot print a Java object to the terminal: " + e);
     
            }
        }
     
    }

  2. #2
    Super Moderator Norm's Avatar
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    Default Re: Why is this working?

    it returned the arguement.
    Please copy the full contents of the command prompt window and paste it here so we can see what happened.
    If you don't understand my answer, don't ignore it, ask a question.

  3. #3
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    Default Re: Why is this working?

    Thank you Norm:

    I executed the code from VS Code.
    What you see above is the full content of the code I run.

  4. #4
    Super Moderator Norm's Avatar
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    Default Re: Why is this working?

    What happens when the program is executed? What is printed on the screen?
    What did you expect to see?

    Note: You have used the word Square in the generic code where normally the coding would use the letter E.
    I believe that your code takes any Object for the args to the method.
    If you don't understand my answer, don't ignore it, ask a question.

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