Reversing an array

im getting incorrect output in my code of reversing an array,plz help

Code Java:

---

import java.util.*;
class a
{
public static void main(String args[])
{
int i,temp;
int []a=new int[5];
Scanner sc=new Scanner(System.in);
System.out.println("Enter the elements of the first array");
for(i=0;i<5;i++)
{
a[i]=sc.nextInt();
}
for(i=0;i<2;i++)
{
temp=a[i];
a[i]=a[4-i];
a[4-i]=temp;
}
System.out.println("The reversed array is:");
System.out.println(a[i]);
}
}

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i think my logic is rite,plz find the bug

Quote:

---

Originally Posted by severus1

im getting incorrect output in my code of reversing an array,plz help

Code Java:

---

import java.util.*;
class a
{
public static void main(String args[])
{
int i,temp;
int []a=new int[5];
Scanner sc=new Scanner(System.in);
System.out.println("Enter the elements of the first array");
for(i=0;i<5;i++)
{
a[i]=sc.nextInt();
}
for(i=0;i<2;i++)
{
temp=a[i];
a[i]=a[4-i];
a[4-i]=temp;
}
System.out.println("The reversed array is:");
for(i=0;i<5;i++)
    System.out.println(a[i]);
}
}

---

---

notice that you just output only ONE element in your original code. after the last loop, the counter "i" had the value of the last iteration, so it output a[2] only.
You have to loop through the entire array to display all its elements, hence for loop i added.

Quote:

---

i think my logic is rite

---

The problem with your code is that it is hardcoded for an array with exactly 5 elements.
Try changing your code to take an array of any length.

thx a lot hexwind

anytime, glad it helped :)