advice for an Odd, Even, Zero counter from input.txt file

Code Java:

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import java.util.Scanner;
import java.io.*;
 
public class assignment4_question3 {
 
    public static void main(String[] args) throws IOException {
 
        String tempLine = "input.txt";
        Scanner fileScan;
 
        fileScan = new Scanner(new File("input.txt"));
 
        while (fileScan.hasNextLine()) {
            int evenCount = 0;
            int oddCount = 0;
            int zeroCount = 0;
 
            tempLine = fileScan.nextLine();
            int num = Integer.parseInt(tempLine);
            int extraNum = num;
 
            extraNum = extraNum % 10;
            extraNum = extraNum /= 10;
 
 
 
            if (extraNum == 0) {
                zeroCount++;
            }
            while (extraNum > 0) {
 
                if (extraNum % 2 == 2) {
                    evenCount++;
 
                } else {
                    oddCount++;
                }
 
 
            }
            System.out.println("Number " + num + " has " + oddCount
                    + " odds, " + evenCount + " evens, " + zeroCount
                    + " zero digits. ");
        }
    }
}

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Okay. This is my code so far.

These are the instructions:

Design and implement a program that read a series of integer numbers from the input file input.txt, determines and prints the number of odd, even, and zero digits in each integer value.

The input.txt contains this:
1234
5008
3245356
352665
2334546


Now. I need to figure out a way to count how many odd, even, and zero digits each of these contains

Here is the correct output:
Number 1234 has 2 odd, 2 even, 0 zero digits.
Number 5008 has 1 odd, 1 even, 2 zero digits.
Number 3245356 has 4 odd, 3 even, 0 zero digits.
Number 352665 has 3 odd, 3 even, 0 zero digits.
Number 2334546 has 3 odd, 4 even, 0 zero digits.

But this is my output [it is horribly wrong and I can't seem to figure out why]:
Number 1234 has 0 odds, 0 evens, 1 zero digits.
Number 5008 has 0 odds, 0 evens, 1 zero digits.
Number 3245356 has 0 odds, 0 evens, 1 zero digits.
Number 352665 has 0 odds, 0 evens, 1 zero digits.
Number 2334546 has 0 odds, 0 evens, 1 zero digits.


Any advice or direction would be unbelievably appreciated.

Hint

Code java:

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int number = 81723;
System.out.println(number % 10);
System.out.println(number / 10);
System.out.println(5 % 2);
System.out.println(6 % 2);

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hmm
u need loop for every number
3 counters, tempnumber

Code :

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for (i=0;i<=number.leght;i++)
tempnumber=Integer.parseInt(number,number.charAt(i));
3 if temp==0 count 0 
....
System.out.println(number,count1,count2...
}/end for

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You are getting remainder and the quotient in the same variable that causes your program to fail each time.
Look at your code carefully and you will come to know.