Printing the Max and Min in an Array

Another one for you guys if you want to help me out... This program is supposed to print the maximum and minimum value in an array. It doesn't. There's a problem in my logic and I cannot figure it out! I've been staring at it too long.

I'm new to Java, that's why all these are pretty simple to you gurus... thoughts? :)

EDIT: I lied, I wanted first and second maximum numbers. Sorry :$

Code Java:

class A3Q3b
{
public static void main (String[] args)
{
// DECLARE VARIABLES/DATA DICTIONARY
int [] a; // GIVENS: the array of values
int index; // INTERMEDIATES: index through array
int first, second; // RESULTS: values of Max and Second Max
System.out.println( "Please input the array: " );
a = ITI1120.readIntLine();
// BODY OF ALGORITHM
first = a[0]; second = a[0];
index = 1;
while (index > a.length)
{
if (a[index] < first)
{
second = first;
first = a[index];
}
else
{
if (a[index] < second)
{
second = a[index];
}
}
index = index + 1;
}
System.out.println("The maximum number is " + first);
System.out.println("The second number is " + second);
}
}

Re: Printing the Max and Min in an Array

Are your <'s and >'s backwards? And probably easier to use a for loop to count through an array

int min = a[0];

int max = a[0];

for(int i = 0;i<a.length;i++) {

if(a[i]>max) max = a[i];

if(a[i]<min) min = a[i];

}

if you wanted first and second highest, as it seems in the code, I would

int min = a[0];

int max = a[0];

int second = a[0];

for(int i = 0;i<a.length;i++) {

if(a[i]>max){

second = max;

max = a[i];

}

if(a[i]<min) min = a[i];

}

Re: Printing the Max and Min in an Array

That did it. Thanks a lot :)