# Help with arrays. Computing averages, sorting the array,

• October 15th, 2012, 03:04 AM
ribb3ntrop
Help with arrays. Computing averages, sorting the array,
//I need to get an array of scores from the user in an applet, then with the array I need to compute the average, count how many scores were above and below the average, sort the array in ascending order (without arrays.sort) and display it all on the applet.

It's fine that they are all integers instead of floats or doubles.

The average keeps coming out weird. I'll put a number in ten times and then it will give me an average lower than that number. And the below average always shows it gets more than it should.

import java.applet.Applet;
import java.awt.*;
import java.awt.event.*;

public class Practice extends Applet implements ActionListener {

Label prompt1;
TextField input1;
Label prompt2;
TextField input2;
boolean done;
int number;
int computeAverage;
int aboveAverage;
int belowAverage;
int next;
int[] score = new int[10];

//A bubble sort I found on the internet, I don't know how to implement it.

for(int x = 0; x < score.length; x++)

for (int y = 0; y < score.length - 1; y++){
int tempa = score [y];
int tempb = score [y+1];
if(score[y] > score[y+1]){
score[y]=tempb;
score[y+1] = tempa;
}
//My method that gives an average lower than it should be.

int computeAverage(int score[], int length) {
int total = 0;
for (int counter = 0; counter < score.length; counter++)
total += score[counter];
int average = total / score.length;
return average;

}
//This is supposed to count how many score are above the average, but it always gives one to the next method belowAverage even if it shouldn't.

int aboveAverage(int score[], int length) {
int average = (computeAverage(score, length));
int total = 0;
for (int counter = 0; counter < score.length; counter++) {
if (score[counter] >= average) {
total++;
}
}
{
}
}

//This one always says that there is one below average even if there isn't.

int belowAverage(int score[], int length) {
int average = (computeAverage(score, length));
int total = 0;
for (int counter = 0; counter < score.length; counter++) {
if (score[counter] < average) {
total++;
}
}
{
}
}

//Normal working textfield and prompt.

public void init() {
prompt1 = new Label("Enter a Score");
input1 = new TextField(10);
}

//I need to get my sorted array printed here somehow.

public void paint(Graphics g) {
g.drawString("Enter -1 to quit early", 10, 50);

if (done) {
g.drawString(
"The class average is "
+ (computeAverage(score, score.length)), 10, 90);
g.drawString(
"The # of scores greater than or equal to the average is "
+ aboveAverage(score, score.length), 10, 110);
g.drawString("The # of scores less than the average is "
+ belowAverage(score, score.length), 10, 130);
}
}

public void actionPerformed(ActionEvent e) {
number = Integer.parseInt(input1.getText());
if (number > 100) {
showStatus("Scores over 100 are invalid");
}

if ((number < 0) || (next >= 9)) {
done = true;
input1.setEditable(false);
showStatus("No more scores can be entered");
} else {
score[next++] = number;
}

repaint();

}
}
• October 15th, 2012, 11:39 AM
KevinWorkman
Re: Help with arrays. Computing averages, sorting the array,
When posting code, please use the highlight tag to preserve formatting.

Your first step is to figure out which part of this fails. Step through this with a debugger, or at least add some print statements, to figure that out. You have to test each part of your program in isolation instead of giving us a whole big mess and saying that it doesn't work.

Why not use Arrays.sort() instead of trying to implement an algorithm you aren't even sure works?