EASY [comparing two vectors of strings]

Hello,
i have two vectors containing strings.These two vectors they dont have the same length.
I need to compare the strings between vector A and vector B ,and find sets of similar strings.
At the end i need to delete the similar strings form vector A.

Thank you for your help a priori.

You can check if a Vector of Strings contains a specified String. To do that, you envoke the Vector.contains(String) method (which returns a boolean). You would just need to loop through Vector A and envoke the contains() method on Vector B for each of Vector A's indexes.

As for removing the similar Strings, you can loop through Vector A and use the Vector.remove(Object) method, and send it the Strings that you know are similar between the two Vectors. Or, if you were particularly lazy, you could call A.removeAll(B);. I believe that call *should* remove all the elements from Vector A that Vector B also has.

I think this answer will be helpful. I will try to work it out now.
Below there is the output of the two vectors A and B as an example.
i hope its helpful

Code :

---

----------(suitableForProcess>=1,hasTypeProfile>=1,hasTypicalConsumption>=1,hasLoadProfile>=1,¥hasTypicalConsumption.(Watt>=30,Watt<=30),¥hasTypeProfile.(MediumShift,Shiftable,TypeProfile,Profile),¥hasLoadProfile.(ConstantLoad,LoadProfile,Profile),¥suitableForProcess.(WatchingPhoto,MentalProcess,Process,EnvironmentTemperatureRegulation,Functionality,NormalSafetyLevel,SafetyLevelRegulation,MediumSecurityLevel,SecurityLevelRegulation,SoftLightLevel,LightLevelRegulation,PlayPhoto,!HighSecurityLevel,!LowSecurityLevel,!BrightLightLevel,!LowLightLevel,!NoLight,!NormalLightLevel))
----------(suitableForProcess>=1,isSuggestedForWeatherCondition>=1,isSuggestedForOutdoorLuminosity>=1,isSuggestedForTemperature>=1,¥isSuggestedForOutdoorLuminosity.(HighLuminosity,OutdoorLuminosity,Weather,!LowLuminosity,!MediumLuminosity),¥isSuggestedForWeatherCondition.(Sunny,WeatherCondition,Weather,!Cloudy,!PartlyCloudy,!Rain),¥isSuggestedForTemperature.(Heat,Temperature,PhysicalStatus,Characteristic,!Cold,!Normal,!Refreshing,!Warmth),¥suitableForProcess.(BodyProcess,Process,EnvironmentTemperatureRegulation,Functionality,Cook,KitchenWork,KitchenLight,LightLevelRegulation,VentilationFunctionality,Eating))

---

Sorry misread... As started before iterate through one of the vectors and compare against the contents of the other.

Michael.

Do you mean java.util.Vector when you say 'vector', or something else? Your problem sounds like it would be natural to solve it with java.util.Set:
The Set Interface (The Java™ Tutorials > Collections > Interfaces)
The method names will be familiar from aussiemcgr's post, but I suspect the implementations / performance (because java.util.Vector implements List) may vary greatly.

im sorry
noob mistake
i have two vectors containing ITEMS .At the end of the loops of the vectors i get 2 Items and i have to compare them .
they look like this:

ITEM A:---------->suitableForProcess>=1,hasTypeProfile>=1,(Watt>=30 ,Watt<=30),¥hasTypeProfile.(MediumShift,Shiftable, TypeProfile,Profile),¥hasLoadProfile.(ConstantLoad ,LoadProfile,Profile),¥suitableForProcess.(Watchin gPhoto,!NoLight,!NormalLightLevel)

ITEM B:--------->suitableForProcess>=1,isSuggestedForWeatherCondit ion>=1,¥isSuggestedForOutdoorLuminosity.(HighLumin osity,OutdoorLuminosity,Weather,!LowLuminosity,!Me diumLuminosity),¥isSuggestedForTemperature.(Heat,T emperature,PhysicalStatus,Characteristic,!Cold,!No rmal,!Refreshing,!Warmth)

After comparing those items,ill have to eliminate from Item A equal descriptions:
in this example suitableForProcess>=1 must be eliminated

**Note:those are semantic descriptions