simple arithmetic problem

Hello. I'm new here and simply looking for help to a problem I'm having.

I have a program requesting user input for two variables as integers. I then have a third variable set as a double that I would like to use to divide the two integers and give me a decimal with no more than 2 decimal places.

I'm fairly certain this has something to do with me trying to set a double equal to the division of 2 integers. How would I get this to work?

so you want to ask the user to type in 2 integers?

then divide the first integer by the second integer? and store this value in a double.

then print out the double to 2 decimal places?

Quote:

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Originally Posted by nadrii

I'm fairly certain this has something to do with me trying to set a double equal to the division of 2 integers. How would I get this to work?

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Well first of all, if you divide an int by an int, you get a truncated (or cut off) answer, setting the answer as a double simply adds .0 at the end. What is it that you're confused with? Are you trying to add the two ints and divide by a double? If so, are you confused with how to have the answer go to 2 decimal places? How much have you already done and what specifically do you have trouble with?

*edit* darn, too slow once again :(

to read in user input you need to use the Scanner class.

first of all import the Scanner class: import java.util.Scanner;

then in your main class body you want to create a new scanner object and read in 2 integers from the user.

use this:

Code :

---

int num1, num2;
Scanner scan = new Scanner (System.in);
System.out.println("Please enter 2 integers:");
num1 = scan.nextInt();
num2 = scan.nextInt();

---

Ah i think its parseDouble you need to convert int to double.

at the moment i have:

Code :

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package testing;
 
import java.util.Scanner;
import java.text.DecimalFormat;
 
public class NewMain {
 
    public static void main(String[] args) {
 
        int num1, num2;
        double num3, num4, divided;
        Scanner scan = new Scanner(System.in);
        System.out.println("Please enter 2 integers:");
        num1 = scan.nextInt();
        num2 = scan.nextInt();
        num3 = Double.parseDouble(Integer.toString(num1));
        num4 = Double.parseDouble(Integer.toString(num2));
        divided = num3 / num4;
        System.out.println(divided);
    }
}

---

it reads in 2 integers, converts them to doubles, stores the division result in a double called divided.

Now you somehow need to format the double 'divided' to 2 decimal places

The entire program works just fine. I've scanned in two separate integers using two separate print statements. They're now stored in two separate variables, let's say A and B (for reference).

I now have a third variable C declared as a double. I would like to do the following:

Code :

---

C = A / B;
System.out.print("The value of C is " + C + ". ");

---

However, C always comes out as 0 even though A and B up to this point are being calculated just fine. In my code right now I have print statements verifying this. I'd like to print C so that it actually does this division properly. I figured the problem lied with dividing two integers and setting that equal to a double. I'd like to know how I can get this to work.

edit:
Just saw the above post, going to try it.

Yes you should try my code above to see if its what youre looking for.

I had the same problem with dividing two integers and trying to just store the result as a double.

it just gave 0.0 everytime.

Well right now I'm trying the following:

Code :

---

A = (int) Double.parseDouble(Integer.toString(A));
B = (int) Double.parseDouble(Integer.toString(B));
 
C = A / B;
System.out.print("The value of C is " + C + ". ");

---

The reason that int in parenthesis is added is because my compiler is suggesting it as a solution to an error. The way you presented it to me wasn't working. And after I put that int there C is still coming out as 0.0.

The key point learnt here i think is converting the ints to doubles before performing the division.

If you want a double from the division of the int's, you need to specify you are doing floating point math by casting the num/denom to double types

Code :

---

double d = a/(double)b;//assuming a and b are of type int

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@djl1990, I recommend you read the following link - a few of your posts come quite close:
http://www.javaprogrammingforums.com...n-feeding.html

Code :

---

int test1, test2;
 
test1 = (int) Double.parseDouble(Integer.toString(A));
test2 = (int) Double.parseDouble(Integer.toString(B));
 
C = test1 / test2;
System.out.print("The value of C is " + C + ". ");

---

Still getting 0.0 :(

You'll need 5 variables

A & B (the two integers read in from user input)
C = A parsed to a double
D = B parsed to a double
and E = C / B

Try it that way.

Try this mate

Code :

---

 
        int A, B;
        double C, D, E;
        Scanner scan = new Scanner(System.in);
        System.out.println("Please enter 2 integers:");
        A = scan.nextInt();
        B = scan.nextInt();
        C = Double.parseDouble(Integer.toString(A));
        D = Double.parseDouble(Integer.toString(B));
        E = C / D;
        System.out.println("1st number divided by the 2nd number = " + E);

---

Quote:

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Originally Posted by copeg

@djl1990, I recommend you read the following link - a few of your posts come quite close:
http://www.javaprogrammingforums.com...n-feeding.html

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Sorry, I do try and explain steps though. I wont post code solutions in future.

Ooo, that worked! I realized just now I had set E to a float a while back as I was trying to solve this problem. Converting them to doubles using this method worked though.

My only issue now, though, is limiting E to two decimal places. Would you happen to know how I can do that?

I'm looking around a bit and seeing some stuff about using pound signs to designate how many decimal points will be printed out. Anyone know anything about this?

edit:
This post cleared it up for me. Thanks a lot!