Help with code that prints number of evens, odds, and 0's

Okay, so my assignment was this: Design and implement an application that determines and prints the number of odd, even, and zero digits in an integer value read from the keyboard.
What should happen is i enter a random number: 1234567890. it would then print out: There are 5 odd numbers. There are 4 even numbers. There are 1 zeroes.

Here is my code i have written so far:
public static void main (String[] args)
{

int zero = 0, odd = 0, even = 0, length, left = 0;

String string;
System.out.print ("Enter any positive integer: ");
string = Keyboard.readString();

length=string.length();

while (left<length)
{
string.charAt(left);
left++;
if (string.charAt(left) == 0)
zero++;
else if (string.charAt(left) % 2 == 0)
even++;
else
odd++;
}

System.out.println ("There are: "+ zero + " zeroes.");
System.out.println ("There are: "+ even + " even numbers.");
System.out.println ("There are: "+ odd + " odd numbers.");

}
}

The program is compiling just fine, but when i run it i get this error:
Exception in thread "main" java.lang.StringIndexOutOfBoundsException:String index out of range: 9
at java.lang.String.charAt(String.java:558)
at Three.main(Three.java:32)

Please Help.
Thanks

In your While loop, you increment your "left" integer too early. Therefore, when you check the character at left, it will be out of range. Just place your increment operator - "left++;" - at the end of the while loop.

Solved. Dude I love you.