Arrays

Code Java:

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import java.util.Scanner;  
public class Max_Number {
  public static void main(String[] args) {
    Scanner input = new Scanner(System.in);
 
    double[] myList = new double[6];
 
    double max = myList[0];
    for (int i = 1; i < myList.length; i++) {
      if (myList[i] > max) max = myList[i];
 
        System.out.print("Enter a number: ");
      myList[i] = input.nextDouble();
 
    }
 
 
    int countGreater = 0;
 
    for (int i = 0; i <myList.length; i++) {
        if(myList[i] > max)
        countGreater++;
    }
 
    System.out.println("The max is " + max);
    System.out.println("The number of values greater than the max is " + countGreater);
  }
}

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The question asked me to write a program that reads 5 numbers, computes the max and finds out how many numbers are above the max. Please help!!!!!!

With what?

Quote:

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Originally Posted by ruffu054

computes the max and finds out how many numbers are above the max.

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Simple. None!

How can you have any numbers greater than the max number?

Its not giving me the correct output when run the program.

I dont make up the problem I just try to do them

still confused?????????????

Then I suggest you seek clarification from your teacher. Given the numbers: 1 6 4 2, the largest number is 6 and there are no numbers bigger than 6. So the question does not make sense or you have misunderstood it.