Loop to note position of lowest number

Hi guys,

I have a password key which is "password12Qcb6z:!sh:&BYztwYTPM" which i have repeating a number of times in a 1d array.

What i am trying to create an array where numbers are assigned starting with 1, and they are assigned first by alphabetical order, and second, where the same letter appears twice, by position in the word.


for example:

C O N V E N I E N C E
1 10 7 11 3 8 6 4 9 2 5


my key is alot longer than "CONVENIENCE" its roughly 328 characters long ("password12Qcb6z:!sh:&BYztwYTPM" repeated ). so i have a 1d int array array which i want to map out 1-328 following the rule above starting wit the lowest character in its ascii values 32 = SPACE to ~ = 127. so i then have a array mapping out 1-328 ...


I have this code so far

Code :

---

int v=0, count=0, r=32; // 33 is the first usable ascii character in test file 
int[] colprintorder = new int[numberofcols];
 
 
while(r<=127) // loop unit last usable ascii char
{
    for(int i=0;i<passwordinbyte.length;i++) // go through each cell of  the array
    {
 
       if (r == passwordinbyte[i]) // if the value of r is the same as what is in passwordinbyte  map its position storing in colprintorder
       {
       colprintorder[count] = i ;
       count++; // next cell in the array
       }
    }  
 r++; // look for the next characters ascii value  32-127
}
 
for(int a=0; a<colprintorder.length; a++) // print out colprint order
{
   System.out.println( colprintorder[a] + " " );
}
 
System.out.println("lengthhrr" +passwordinbyte.length);

---

Here is my output using the code snippet above:


http://i57.photobucket.com/albums/g2...e2k/lolcat.jpg


it appears theres somthing wrong with my code but i dont know what can you guys help me ?


thank you

I have added a better testing print out below

Code :

---

 Coloumn print order: 
   17   19   10     8       9     12    14    15    11    1     7    16    5    0      6     2      3     18    4   13
 Password in bytes: 
  112   97  115  115  119  111  114  100   49   50   47   70   50  123   52   57  104   33  118   43
 Password in characters: 
    p    a       s       s     w      o      r      d       1    2      /     F     2     {       4     9      h     !     v     +

---

as you can see the lowest ascii number charcter is '+' which has the value of 43 however it has been put at position of 13. (http://www.cs.utk.edu/~pham/ascii_table.jpg)

the coloumn array need to map the password in bytes in order. Does anyone know what im doign wrong

Ok, I'm a little confused (maybe this is above me or something).

So, you are wanting to get the ASCII values of all of the characters, then determine, based on their ASCII values, which come first, second, third, ect.

If so, I am unsure why you have all that code. You can convert a String to a char[] using the String.toCharArray() method, then sort the char[] with the Arrays.sort(char[]) method, then do whatever with the sorted array.

When I input CONVENIENCE in the code below:

Code java:

---

import java.util.Arrays;
 
public class ASCIITesting
{
    public static void main(String[] args)
    {
    	String input = "CONVENIENCE";
    	char[] charArr = input.toCharArray();
    	Arrays.sort(charArr);
    	for(int i=0;i<charArr.length;i++)
    		System.out.print(Character.toString(charArr[i]));
    }
}

---

It outputs:

Quote:

---

CCEEEINNNOV

---

which is the word sorted based on each character's ASCII value.
Similarly, if I input password12Qcb6z:!sh:&BYztwYTPM it outputs:

Quote:

---

!&126::BMPQTYYabcdhoprssstwwzz

---

Am I totally off?

yes you are off but after 2 hours if staring at the screen i figured it out .

Than kyou for your help :)