Difference in the code on changing logical operators

Code :

---

import java.util.Scanner;
 
	class TicketPriceWithDiscount {
		public static void main(String args[])
		{
			Scanner myScanner = new Scanner(System.in);
			int age;
			double price = 0.00;
			char reply;
 
			System.out.print("How old are you? ");
			age = myScanner.nextInt();
 
			System.out.print("Do you have a coupon? (Y/N)");
			reply = myScanner.findInLine(".").charAt(0);
 
			if(age >= 12 && age < 65){
				price = 9.25;
				}
			if(age < 12 || age >= 65){
				price = 5.25;
			}
			if(reply == 'Y' || reply =='y'){
				price -= 2.00;
			}
			if(reply !='Y' && reply !='y' && reply !='N' &&
				reply != 'n' ){
					System.out.println("Huh");
				}		
		}
 
}

---

for the above code i am wondering if i were to change the 1st IF condition

Code :

---

if(age >= 12 && age < 65)

---

into

Code :

---

if(age >= 12 || age < 65)

---

would there be a difference?? right now i am having problems differentiating && and ||. just started out programming here

&& requires both statements to be true before the if statement will execute, whereas
|| requires only 1 statement to be true before the if statement will execute.

Example

Code :

---

public class lotus {
     public static void main(String[] args){
          int a = 5, b = 3;
          if(a == 5 && b == 3) System.out.println("Look they both are true");
          if(a == 5 && b == 7) System.out.println("Look only one is true, but using and so not printed");
          if(a == 5 ||  b == 3) System.out.println("Look they both are true, so or will print");
          if(a == 5 ||  b == 9) System.out.println("Look only one is true, by or means it will still print me");
          if(a == 9 ||  b == 9) System.out.println("Neither are ture so im not printed");
     }
}

---

ok i got it thanks

No problem, if thats everything could you please mark this as solved.

Chris