how to write an if statement which evaluates 3 dialogue boxes

Hi all

Im trying to write a code that has a for loop which iterates through 3 instance variables, the 3 instance variables are each set using a confirm dialogue box so if the user clicks yes they ae set with the value true and if the user clicks no they are set wit the value false. I have done this and it works fine,

however the next step is to display an alert message if less than 2 of the dialogue boxes evaluate to true. I am extremely stuck on this and ive been working on it for hours now. im thinking I will use an if statement but I dont know how to evaluate the 3 instance variables. I know how to work with one but im not even sure if its possible to evaluate 3 and have the condition evaluate to true if less tan 2 of theinstance variables evaluate to true?

I hope someone can help as im really stuck on this now. :-L

just to clarify, what im trying to do is write a loop following these guidelines:

if less than 2 of the dialogue boxes result in true
do something

or it may be possible to do it like this??:

if less than 2 of the instance variables are equal to true
do something

this doesent have to be a loop if there is another way to do it, i just think a loop is the way I need to do it, however as i am a noob to programming I could ofcourse be wrong!

sorry for not adding code but I am currently moving house so have no internet connection for my pc. I am posting these messages via a mobile phone.

Thanks in advance to anyone who attempts to help me

You can count how many are checked....quite a few ways to do this. Here's two methods (there are more than this though):
Using a loop

Code :

---

int x = 0;
for ( int i = 0; i < 3; i++ ){
     if ( value[i] ){ x++; }
}
if ( x < 2 ){
//do something
}else if ( x == 2 ){
//2 are checked, do something else
}else{
//all are checked, do something else
}

---

In a single statement:

Code :

---

if ( ( value[0] && value[1] && !value[2] ) ||
		( value[0] && !value[1] && value[2] ) ||
			( !value[0] && value[1] && value[2] ) ){
	//only 2 are checked
}

---

All code assuming value is an array containing your booleans

hi copeg, thankyou for the reply, i worked this out in the end last night. I did it the same as your second example & ive tested it & it all works. thankyou again for the assistance

Could you also do this without the array. for exemple by just checking

Code :

---

if ( x==1)
            {
             //do something
            }

---

etc etc??

also,

how then would you get the dialog boxes to ask a question (to get the true/false)?? where would you store these true false boolean answers?

Am i making sense?

Yes, it can be done without arrays, but you can't compare booleans with integers in Java.

Code :

---

boolean val1 = true;
if (val1 == 1) // Syntax error

---

However, you will still need 3 variables to put the values in. Copeg chose an array because that's one of the easiest ways to store a list of variables.

There are two main ways to get a dialog box: make it yourself, or use the JOptionPane class.

Code :

---

JOptionPane.showConfirmDialog(null,"Do you confirm?");

---

Note that showConfirmDialog actually returns an integer value, so you have to compare it to the static response values stored in the JOptionPane class:

Code :

---

if (JOptionPane.showConfirmDialog(null,"Do you confirm") == JOptionPane.YESOPTION)
{
    // yes selected
}

---

Ah right I'm with you!!

The only thing is, in the course that I'm doing, we haven't yet learnt about arrays so will not be able to use them.

If I put the answers into 3 variables, how would I then check to see if 2 or more of the variables do contain a 'true'?

could I do something that checks "do you want yes or no" - then if yes is chosen it adds 1 to a value. This would be repeated 3 times and then if the value is 2 or more then something is executed?

I'm sure I'll figure this out but some input would help.

thanks so much (in advance).

John

No worries - I've just cracked it!!

Basically I craeted another varaiable and each time added to to it. All's good

Thanks