Diamond perimeter with loop

Hi. I've beed trying to do this for days but I can't.

http://img831.imageshack.us/img831/8334/diamondc.png

I got the program to do the whole diamond but I don't know how to take out all the asterisk. ¿Any idea?

This is my code:

Code :

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public class diamond
{
	public static void main(String args[])
	{
		int i=0,j,k,n=4;
		for(k=1;k<=n;k++) {
			for(i=0;i<=n-k;i++) {
				System.out.print(" ");
			}
			for(j=1;j<=k;j++) {
				System.out.print("*");
			}
			for(j=1;j<=k-1;j++) {
				System.out.print("*");
			}
			System.out.println("");
		}
		for(k=1;k<=n;k++) {
			for(i=0;i<=k;i++) {
				System.out.print(" ");
			}
			for(i=1;i<=n-k;i++) {
				System.out.print("*");
			}
			for(j=0;j<=n-k-2;j++) {
				System.out.print("*");
			}
			System.out.print("\n");
		}
	}
}

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Apart from the first and last line, each line has: N spaces, star, M spaces, star. All you have to do is work out what N and M is for each line.

Inside the outer loop, keep a flag, which will keep track if the very first * has been printed, don't let the program draw * again, unless it's the last index of inner loop.
Note: Don't forget to reset the flag.

Quote:

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Originally Posted by Mr.777

Inside the outer loop, keep a flag, which will keep track if the very first * has been printed, don't let the program draw * again, unless it's the last index of inner loop.
Note: Don't forget to reset the flag.

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Your refering about IF and else statement right?

yes that is what he is saying :)

Quote:

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Originally Posted by Rage1337

Your refering about IF and else statement right?

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Yes, sorry for not making it clear.