binary conversion..

anyone can make me a simple program that converts decimal to binary and to decimal again..

i just want to know how to make its structure in program...
its not that easy. althoug i know the process of it and i cant do it it PAPER.

and i will study its algorithm and then apply it in converting in hex and octal..

please...

im getting some hard time with this

Some time ago I wrote this in C++. You shouldn't have a problem reading the Syntax, if you do let me know.

Code :

---

std::string conv(std::string number, int startBase, int endBase){
    if(startBase > 16 || endBase > 16) return "BASE ERROR";
    char NUMS[] = "0123456789ABCDEF";
    std::string result = "";
    int temp = 0, x;
    bool found = false;
    for(int i = 0; i < number.length(); i++){
        for(x = 0; x < startBase; x++){
            if(NUMS[x] == number[number.length()-(i+1)]){
                found = true;
                break;
            }
        }
        if(!found) return "NUMBER ERROR";
        temp += (x*power(startBase, i));
    }
    do{
        result.push_back(NUMS[temp%endBase]);
        temp /= endBase;
    }while(temp != 0);
    return std::string(result.rbegin(), result.rend());
}
 
long long power(int num, int pow){
    if(pow == 0) return 1;
    return num*power(num, pow-1);
}

---

Enjoy the studying of it :)

Regards,
Chris

im not really familiar with C .. can you please convert it into java... ?? ill study both of it ,in C and in Java

sori for that....

Code :

---

public String conv(String number, int startBase, int endBase){
    if(startBase > 16 || endBase > 16) return "BASE ERROR";
    char NUMS[] = { '0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F' };
    String result = "";
    int temp = 0;
    int x;
    boolean found = false;
    for(int i = 0; i < number.length(); i++){
        for(x = 0; x < startBase; x++){
            if(NUMS[x] == number.charAt(number.length()-(i+1))){
                found = true;
                break;
            }
        }
        if(!found) return "NUMBER ERROR";
        temp += (x*power(startBase, i));
    }
    do{
        result += NUMS[temp%endBase];
        temp /= endBase;
    }while(temp != 0);
    return new StringBuilder(result).reverse();
}
 
public long power(int num, int pow){
    if(pow == 0) return 1;
    return num*power(num, pow-1);
}

---

I think i've made all the conversions...there are not many lol! I'm amazed you needed me to do it :P

Regards,
Chris

sori to bother you.. hehehe anyway tnx for that,!!..

ah one more thing chris..


what does java use? ASCII or UNICODE?

i notice something using .read() method of InputStreamReader class

once i input some numbers or characters it returns something like ASCII or UNICODE.
im curious of what kind of character code does java use.

It uses ASCII, read() returns an integer which represents the ASCII value for the character it has read. If you enter 'A' it will return 65 :).

At least as far as I'm aware, I don't have a compiler infront of me to test hehe!

Regards,
Chris

hehehe.. tnx for the info chris!! hahah \m/

ah last chris.. the program that you gave was a hexadecimal conversion right? hehe

No, it will go from any base to any base, asuming it is a base below 16 and given in a String format.

Chris