String to Int

Code Java:

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   import java.io.*;
   import java.net.*;
   import java.util.*;
   import java.lang.*;
   import javax.swing.JOptionPane;
   import java.text.DecimalFormat;
   import java.text.NumberFormat;
   import java.math.*;
 
   public class EchoClient
   {
      public static void main(String[] args)
      {
      // declare objects we require
         Socket  localSocket;
         BufferedReader in;
         BufferedReader kbdInput;
         PrintWriter out;
         String hostname = new String();
         String s, s1;
 
         BufferedReader input = new BufferedReader(new InputStreamReader(System.in));
 
 
 
         System.out.println("Server IP Address : ");
         try
         {
            hostname = input.readLine( );
         }
            catch(Exception e)
            {
               System.out.println("Exception: " + e.getMessage( ) + "has occurred");
            }
 
 
         try
         {
         // create a socket connected to remote Port 9999; DNS lookup is automatic
            localSocket = new Socket (hostname, 9999);
 
                  // acknowledgement of connection request
            System.out.println(" Connection made with " + localSocket.getInetAddress( ) +
                  "\nRemote Port: " + localSocket.getPort( )+
                  "\nLocal Port: " + localSocket.getLocalPort( ));
 
         // set up data streams in and out of socket and from keyboard
            in = new BufferedReader(new InputStreamReader(localSocket.getInputStream( )));
            out = new PrintWriter(localSocket.getOutputStream( ));
            kbdInput = new BufferedReader(new InputStreamReader(System.in));
 
         // Lab 2 - (2)(a) Bob uses PublicAlice key to encrypt a plaintext message M
 
            BigInteger n,e, p,q,d, exponent;
 
            s1 = in.readLine( );
            System.out.println("Value of n: "+s1);
            n = new BigInteger(s1);
 
            s1 = in.readLine( );
            System.out.println("Value of e: "+s1);
            e = new BigInteger(s1);
 
 
         // while we have a connection
            while (true)
            {
               BufferedReader buff = new BufferedReader(new InputStreamReader(System.in));
            // read keyboard to String
               //s = kbdInput.readLine( );
            // Lab 2 - (2)(b) Bob uses PublicAlice key to encrypt a plaintext message M
               char M;
 
                           System.out.println("Enter value of M: ");
                             String word = buff.readLine(); 
 
 
                           int j = Integer.valueOf(word).intValue();
               BigInteger b1 = BigInteger.valueOf(j);                     
               BigInteger num = b1.modPow(e,n);
               NumberFormat matter = new DecimalFormat("#0");
                             System.out.println(matter.format(num));
 
 
 
               out.println(num);
               out.flush();   
               //}         	
               System.out.println(in.readLine( ));
            }
         }
            catch (UnknownHostException e)
            {
               System.out.println(e.getMessage( ));
            }
            catch (IOException e)
            {
               System.out.println(e.getMessage( ));
            }
      }
 
   }

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System.out.println("Enter value of M: ");
String word = buff.readLine();


int j = Integer.valueOf(word).intValue();

i am try to convter a string, like eg: HI into int. However it give me error and how to do anyway?

The Integer.valueOf method expects a String representation of a number, e.g. "45". It doesn't know the int value of "HI", neither do I. What is the int value you think "HI" should have?

the value of HI is 72, 73 because H in ascii is 72 ans I is 73. But now i want HI together is it need to (72*73)=HI?

Hint:

Code java:

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System.out.println((int)'a');

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Quote:

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Originally Posted by Joy123

the value of HI is 72, 73 because H in ascii is 72 ans I is 73. But now i want HI together is it need to (72*73)=HI?

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'72, 73' is not an int. The compiler is not a mind-reader - you can get the UNICODE value of each character (equivalent to ASCII for the latin alphabet) by casting to an int as Junky shows above. What you do with the two character values is up to you.

How to do? Can show example?

If you want to convert some int values to single character Strings and then concatenate them.
If the int values can be cast to char, the String class has a constructor to create a String.
Then use + to concatenate the Strings.

Can you give some examples of a String and the int value that you want to convert it to?

Quote:

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Originally Posted by Joy123

i am try to convter a string, like eg: HI into int. However it give me error and how to do anyway?

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Pardon me if this is a noob answer....

But have you tried using parseInt?

i.e:
String HI = whatever it equals
int hi = Integer.parseInt(HI);

I read the question as: How to convert the String "HI" to an int value.
Try this: System.out.println("HI=" + Integer.parseInt("HI", 26)); // HI=460

Anyway Thank for tips and guide

Quote:

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Originally Posted by Norm

I read the question as: How to convert the String "HI" to an int value.
Try this: System.out.println("HI=" + Integer.parseInt("HI", 26)); // HI=460

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:) nice one - base 26 does have some uses after all!

What is the word for that base? Hexadecimal for 16. My latin is too old.

Quote:

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Originally Posted by Norm

What is the word for that base? Hexadecimal for 16. My latin is too old.

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Hexavigesimal - Wikipedia, the free encyclopedia

Code :

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public class Test{
    public static void main(String[] args){
        String HI = "HI";
        String s = "";
        for (int i=0;i<HI.length();i++){
            char a = HI.charAt(i);
            int j = a;
            s=s+j;
        }
        System.out.println(s);
    }
}

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navis- why have you resurrected an old post? Why have you attempted to spoon-feed the OP an answer instead of offering hints? I'm pretty sure that your attempt is incorrect anyway, but since the OP never truly specified what the requirements were, we can't tell.

Either way, I don't really see the point of your post. I appreciate you trying to help, but spoon-feeding is NOT helping, and resurrecting old threads is pretty fruitless.

My apologies KW. I got the point.

Quote:

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Originally Posted by navis

My apologies KW. I got the point.

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It's okay. Helping out is great, but spoonfeeding answers is not great, and resurrecting old posts usually is a waste of time. Welcome to the forums.