Plz.. help me out to understand the java concepts regarding arrays

when i write the code:

int a;
System.out.println(a);

compiler flags an error that a might not have been initialized.

but when i write this

int [] a= new int[10];
System.out.println(java.util.Arrays.toString(a));

compiler doesnot flag any error
and gives a output
[0,0,0,0,0,0,0,0,0,0]

I want to understand from where the integers stored in the array are getting initial value 0 without any expilicit initialization.
Plz.. help me out i am a beginner in java .

That's just the default value populated in an array- 0 for ints, null for Objects. It's similar to how class variables (not method variables) get a default value, even if you don't explicitly give them one.

Quote:

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Originally Posted by KevinWorkman

That's just the default value populated in an array- 0 for ints, null for Objects. It's similar to how class variables (not method variables) get a default value, even if you don't explicitly give them one.

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thanks a lot kevin for ur help.

Quote:

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Originally Posted by Arindam Sarkar

thanks a lot kevin for ur help.

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No problem. Keep in mind that had you done this instead:

Code java:

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int [] a; //no declaration!
System.out.println(java.util.Arrays.toString(a));

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...you would have received a similar error.