Converting Hex to Decimal

hi... its me again...


can someone help me? with this??

/*Hexadecimal to Decimal

Given a hexadecimal number as input. Convert this number to its decimal equivalent.
Catch all exceptions that maybe caused by the program.
It is up to you what will be the statements to be executed by the computer when an exception occurs.
**/

im having hard time implementing the exceptions... but i guess i can do anything about it.. its very hard to be a student :)
please if anyone can help me

we have the same thread title huh... any way what do you got there so far?

Please post a new topic when you're asking a new question...

I''m assuming that the number being inputted is in a String. In that case, you can use the Integer.parseInt() method;

Code :

---

try
{
Integer.parseInt("3efd",16);
}
catch (NumberFormatException e)
{
     System.out.println("Error! tried to parse an invalid number format");

---

helloworld can you please ,if it is ok.. can you post here the link of my previews post about conversion.. i dont know how to locate it easily. it may help him... the title is

Quote:

---

[SOLVED]numerical conversion...

---

hehe, I was trying to find the link to it, too :P

Here it is: Numerical conversion methods

yah thats it hehehehehe :))

thank you so much... i appreciate it....

how about the code in converting hexadecimal to decimal without using any packages? like
.hexa??? .parseInt?

not sure if applicable or not, but this may spark an idea...maybe

Decimal -> hex

Code :

---

String[] allHex = new String[(16*16*16)-1];
 
String key = "0123456789ABCDEFG";
 
for(int i =0, int counter=0 ; i <16; ++i)
    for(int j =0; j <16; ++j)
        for(int k =0; k <16; ++k)
        {
        allHex[counter] = "" + key.charAt(i) +key.charAt(j)+key.charAt(k);
        ++counter;
        }
 
// allHex now holds all hex values from 0 to FFF...for example allHex[123] = "07B"

---

Maybe you can find a way to work backwards from this

heres another solution to same problem i just solved..using modulus instead this time, and it can convert a single number inputted..instead of generating all values upto desired n
http://www.javaprogrammingforums.com...cimal-hex.html

import java.util.Scanner;


public class N70HexadecimaltoDecimalConverter {

/**
* @param args
*/
//Class for powered
public static int pow(int i, int powerNum) {

return (int) Math. pow( 16, powerNum);
}

public static void main(String[] args) {


Scanner input = new Scanner(System.in);
System.out.print("Enter HexDecimalNumber :" );

String hdN=input.nextLine();
long decNum=0;

for(int i=0;i<hdN.length();i++){
//define the power(exponent)
int powerNum=hdN.length()-i-1;
//extract the chars of String consecutively
int de= hdN.charAt(i);
//format the Hexadecimal to Decimal number
switch(de){
case '0':decNum= 0*pow(16,powerNum)+decNum;break;
case '1':decNum= 1*pow(16,powerNum)+decNum;break;
case '2':decNum= 2*pow(16,powerNum)+decNum;break;
case '3':decNum= 3*pow(16,powerNum)+decNum;break;
case '4':decNum= 4*pow(16,powerNum)+decNum;break;
case '5':decNum= 5*pow(16,powerNum)+decNum;break;
case '6':decNum= 6*pow(16,powerNum)+decNum;break;
case '7':decNum= 7*pow(16,powerNum)+decNum;break;
case '8':decNum= 8*pow(16,powerNum)+decNum;break;
case '9':decNum= 9*pow(16,powerNum)+decNum;break;
case'A':decNum= 10*pow(16,powerNum)+decNum;break;
case'B':decNum= 11*pow(16,powerNum)+decNum;break;
case'C':decNum= 12*pow(16,powerNum)+decNum;break;
case'D':decNum= 13*pow(16,powerNum)+decNum;break;
case'E':decNum= 14*pow(16,powerNum)+decNum;break;
case'F':decNum= 15*pow(16,powerNum)+decNum;break;

}
}
System.out.println("Decimal number is: "+decNum);
}
}

Why not use an array vs that awful switch statement?