Word length frequency help for applet
Hi all, I have been set an assignment in university. I have to create an applet counts the word length frequency and have looked all over to see if anyone else has done this. So far I have been able to work out how to count the number of words and that's all.
It says in my assignment criteria:
"In its simplest form, frequency analysis
calculates the number of words of length 1, 2, 3, ..., n, where n is the length of
the longest word. For example, analysing the sentence “I am a man” would
produce the output “2, 1, 1”." In pretty sure the outcome is 2,1,1 because it has 2 words with 1 letter, 1 word with 2 letters and 1 with 3 letters.
Here is my code so far:
Code :
import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
public class Sykes_J_resitAss extends JApplet
implements ActionListener {
JTextArea textInput; // For the user's input text.
JLabel wordCountLabel; // For displaying the number of words.
public void init() {
setBackground(Color.darkGray);
getContentPane().setBackground(Color.darkGray);
/* Create the text input area and make sure it has a
white background. */
textInput = new JTextArea();
textInput.setBackground(Color.white);
/* Create a panel to hold the button and three display
labels. These will be laid out in a GridLayout with
4 rows and 1 column. */
JPanel south = new JPanel();
south.setBackground(Color.darkGray);
south.setLayout( new GridLayout(4,1,2,2) );
/* Create the button, set the applet to listen for
clicks on the button, and add it to the panel. */
JButton countButton = new JButton("Process the Text");
countButton.addActionListener(this);
south.add(countButton);
/* Create each of the labels, set their colors, and
add them to the panel. */
wordCountLabel = new JLabel(" Number of words:");
wordCountLabel.setBackground(Color.white);
wordCountLabel.setForeground(Color.blue);
wordCountLabel.setOpaque(true);
south.add(wordCountLabel);
/* Use a BorderLayout on the applet. Although a BorderLayout
is the default, I want one with a vertical gap of two
pixels, to let the dark gray background color show through. */
getContentPane().setLayout( new BorderLayout(2,2) );
/* The text area is put into a JScrollPane to provide
scroll bars for the TextArea, and the scroll pane is put in
the Center position. The panel that holds the button and
labels is in the South position. Note that the text area
will be sized to fill the space that is left after the
panel is assigned its preferred height. */
JScrollPane scroller = new JScrollPane( textInput );
getContentPane().add(scroller, BorderLayout.CENTER);
getContentPane().add(south, BorderLayout.SOUTH);
} // end init();
public Insets getInsets() {
// Leave a 2-pixel border around the edges of the applet.
return new Insets(2,2,2,2);
}
public void actionPerformed(ActionEvent evt) {
// Respond when the user clicks on the button by getting
// the text from the text input area, counting the number
// of chars, words, and lines that it contains, and
// setting the labels to display the data.
String text; // The user's input from the text area.
int charCt, wordCt, lineCt; // Char, word, and line counts.
text = textInput.getText();
charCt = text.length(); // The number of characters in the
// text is just its length.
/* Compute the wordCt by counting the number of characters
in the text that lie at the beginning of a word. The
beginning of a word is a letter such that the preceding
character is not a letter. This is complicated by two
things: If the letter is the first character in the
text, then it is the beginning of a word. If the letter
is preceded by an apostrophe, and the apostrophe is
preceded by a letter, than its not the first character
in a word.
*/
wordCt = 0;
for (int i = 0; i < charCt; i++) {
boolean startOfWord; // Is character i the start of a word?
if ( Character.isLetter(text.charAt(i)) == false )
startOfWord = false; // No. It's not a letter.
else if (i == 0)
startOfWord = true; // Yes. It's a letter at start of text.
else if ( Character.isLetter(text.charAt(i-1)) )
startOfWord = false; // No. It's a letter preceded by a letter.
else if ( text.charAt(i-1) == '\'' && i > 1
&& Character.isLetter(text.charAt(i-2)) )
startOfWord = false; // No. It's a continuation of a word
// after an apostrophe.
else
startOfWord = true; // Yes. It's a letter preceded by
// a non-letter.
if (startOfWord)
wordCt++;
}
/* The number of lines is just one plus the number of times the
end of line character, '\n', occurs in the text. */
lineCt = 1;
for (int i = 0; i < charCt; i++) {
if (text.charAt(i) == '\n')
lineCt++;
}
/* Set the labels to display the data. */
wordCountLabel.setText(" Number of Words: " + wordCt);
} // end actionPerformed()
} // end class TextCounterApplet
Any help with this would be greatly appreciated, my deadline is tomorrow and I haven't got a clue! Thanks!
Re: Word length frequency help for applet
Quote:
Originally Posted by
jake6047
Any help with this would be greatly appreciated
Help with what? We don't read minds. If you get errors then copy and paste the full and exact error message and indicate which line it happens on. If it has incorrect behaviour then explain what it does do and what it should do instead. Most importantly ask a specific question. "It doesn't work" provides zero information and is not specific.
Re: Word length frequency help for applet
The code doesn't get errors, I need to get the frequency for the length of words like if I entered " Have a nice day" it would output '2,1,1' the reason for this is because 2 words have the same length and 2 don't. My code lets me know how many words there are and I can't figure out how to do this frequency thing. Sorry for not being very clear.
Re: Word length frequency help for applet
Quote:
Originally Posted by
Junky
If it has incorrect behaviour then explain what it does do and what it should do instead.
Quote:
Originally Posted by
jake6047
For example, analysing the sentence “I am a man” would
produce the output “2, 1, 1”." In pretty sure the outcome is 2,1,1 because it has 2 words with 1 letter, 1 word with 2 letters and 1 with 3 letters.
Dear Junky
I think you have to read posts more carefully before abuse at smb. hurl
Code java:
text = textInput.getText();
String array[]=text.split(" ");
int counter=0;
for(int i=0;i<array.length;i++)
if(counter<array[i].length())
counter=array[i].length();
int intArray[]=new int[counter];
for(int i=0;i<intArray.length;i++){
intArray[i]=0;
}
for(int i=0;i<array.length;i++){
intArray[array[i].length()-1]++;
}
String a="";
for(int i=0;i<intArray.length;i++){
if(intArray[i]>0)
{
a+=String.valueOf(intArray[i]);
a+=", ";
}
}
wordCountLabel.setText(a);
Re: Word length frequency help for applet
Thank you very much Serdar, i've put it into my code and it works perfectly. I really appreciate your help!
Re: Word length frequency help for applet
Quote:
Originally Posted by
serdar
Dear Junky I think you have to read posts more carefully before abuse at smb. hurl
Actually, I believe Junky was on the spot.
The OP's desires were clear, but didn't state what issues he was having, giving the impression that he just wants us to do it for him.
We're here to help and not do people's homework for them. The OP should show goodwill by going off, and attempting it, before reporting back with any errors or concepts he doesn't understand in greater detail.
Edit: The problem with spoon-feeding. Read it, live it, ??eat it?? :D
