how do i try/catch this?

hey people!

im entirely new to java..i need a little bit of help with my assignment code..i want to use try catch. but i dont exactly know where to insert it.i keep getting errors when i insert it after "enter file name". but it says i cannot do that.i want to get a message saying the file isnt existing when wrong file names are inputted by the user.

Code java:

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/**
 * to back up txt files
 * @author (Dinushke Arthnayake) 
 * @version (1.0.0)
 */
import java.util.Scanner;
 
import javax.swing.*;
 
import java.io.*;
 
public class BackItUpTxt
{
    public static void main(String agrs[]) throws IOException
 
    {
        String D_Play = "File does not exist!";
        try
        {
        Scanner yeet1=new Scanner(System.in);
 
        System.out.println("Enter file that you want to backup:");
 
        String yeet2=yeet1.nextLine();
 
 
 
        System.out.println("Enter password to secure your backup:");
 
        String yeet3=yeet1.nextLine();
 
 
            for (int count =6; count > 0 && yeet3 != "acbt"; count--)
            {
            System.out.println("Wrong password. " + (count-1) + " attempts left.Enter password again:");
 
            yeet3=yeet1.nextLine();
        }
 
 
        Encrip.encrip(yeet3,yeet2);
 
        Backup.backup(yeet2);
   }
 catch(FileNotFoundException e){
        JOptionPane.showMessageDialog (null,D_Play);
 
        System.exit(-1);
    }
 
}
}

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Sorry, I don't see this "enter file name" in your code. Have you posted the wrong code?

Quote:

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it says i cannot do tha

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If you get errors, please copy and paste the full text of the message here.

What Exception do you want to catch? What method throws that exception?

Code :

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yeet3 != "acbt"

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Use the equals method to compare Strings. Not == or !=

how exactly do you use the equals method here? please do help me..it stil says that variable yeet1 cannot be found because of the closing bracket before the 'catch' statement..what do you think i should do?how can i access the variable yeet1,yeet2 and yeet3??

Quote:

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.it stil says that variable yeet1 cannot be found

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Please copy the full text of the error message and paste it here.

It sounds like you are having a problem with scope. Variables defined inside of {} are NOT visible or usable outside of the {}. You need to define the variables outside of the {} and give them null or 0 values and then change their values inside of the {}. The new values will then be available when you come out of the {}.

Encrip.encrip(yeet3,yeet2);

Backup.backup(yeet2);

are causing some problems

Quote:

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are causing some problems

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Please explain. If you get error messages, copy and paste here the full text.

Quote:

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Originally Posted by Rex the king

are causing some problems

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This thread is over a year old. I presume the original poster has solve the issue or moved on.