Direction,

Ok, here's the idea.

Point A is a random location,

It wants to travel to point b an adjacent point, I need a method to return the direction of the prime point A, in perspective to point b,

i.e if a point is at, 0,0 and A point (adjacent) Is at point 1,1, The method return north-east (String),

For a closer look here: (Sorry for poor artistic abilitys,)

http://i49.tinypic.com/20awkfa.jpg

The main Point A = at 0,0 (Lavander)

The adjacent point b is at 1,1 (Lightblue),

The method should return that the relationship shared between the points is Northwest,

Keep these in mind:

Quote:

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-Point A is the main point so relationships stem from there,
-The directions are North, Northeast, Northwest, South, Southeast, Southwest, East, West,

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Thanks for reading, I hope someone come's up with a method =P

-Time, o->

pseudo-code:

1. create a vector from point A to B (just subtract their coordinates)
2. Get the angle from the positive X axis (or any axis you want, this is easiest because there's a built in function to do this)
3. Use if/else statements to see which quadrant it's in, and return the appropriate response
in degrees (assuming all angles are measured counter-clockwise from the positive X-axis):
angle == 0: east
0 > angle < 90: north-east
angle == 90: north
90 > angle < 180: north-west
angle == 180: west
180 > angle < 270: south-west
angle == 270: south
270 > angle < 360: south-east

Quote:

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Originally Posted by helloworld922

pseudo-code:

1. create a vector from point A to B (just subtract their coordinates)
2. Get the angle from the positive X axis (or any axis you want, this is easiest because there's a built in function to do this)
3. Use if/else statements to see which quadrant it's in, and return the appropriate response
in degrees (assuming all angles are measured counter-clockwise from the positive X-axis):
angle == 0: east
0 > angle < 90: north-east
angle == 90: north
90 > angle < 180: north-west
angle == 180: west
180 > angle < 270: south-west
angle == 270: south
270 > angle < 360: south-east

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Thank's method created and it works like a charm.